设y=[(x^2+1)/2]*(arctanx)^2-xarctanx+(1/2)ln(1+x^2),求y'以及dy
设y=[(x^2+1)/2]*(arctanx)^2-xarctanx+(1/2)ln(1+x^2),求y'以及dy
求函数y=xarctanx-ln根号下(1+x^2)的导数y'
1.y=x arctanx - 1/2 ln(1+x^2) 求dy 2.y=tan(3x^2+1) 求y的导数即y' 3
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
设y=ln(1+x^2)则dy=
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3.设y=(1+x^2)arctanx,求y" ,y"/x=1 .